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Waec Expos : Mathematics Answers now posted

MATHS THEORY ANSWERS:

(1a)
(y-1)log4=ylog16
log4^(y-1)=log16^y
log4^(y-1)=log4^2*y
y-1=2y
y=-1

(1b)
Distance =speed*time
let the time of the walk be x hours
=>4*(x+0.5)=5x
Because 30 minutes 0.5hours
4x+2=5x
5x-4x=2
x=2hours
=>5*2
=10km

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(2a)
2/3(3x-5)-3/5(2x-3)=3
2/3(3x-5)-3/5(2x-3)=3
lcm=15
=>(6x-10)/3-(6x-9)/9=3
Multiply both sides by 15
15(6x-10)/3-15(6x-9)5=15(3)
30x-50-3(6x-9)=45
30x-50-18x+27=45
12x-23=45
12x=45+23
x=68/12
x=5(2/3)

(2b)
=180-n-88=92-n
Also UTQ=180cm–(sum of 80+92-n+180-m=180(sum of 352-n-m=180
-n-m=180-352
-n-m=-172
-(n+m)=-172
m+n=172degrees

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(3a)
DRAW THE DIAGRAM
tanx=50/x
tan66.4=50/x
x=50/2.289
x=21.844m
x=22m

(3b)
DRAW THE DIAGRAM
Area of =1/2*10*h=45
=>5h=45
h=45/5
h=9cm
Area of parallelogram=L*h
=9*6
=54cm^2
Therefore the area of QTUS=54+45
=99cm

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(4a)
Tnth=a+(n-1)d
Snth=n/2[2a+(n-1)d]
T6th=37
S6th=147
T6th=>37=a+(6-1)d
=>37=a+5d—–(i)
S6th=>147=6/2[2a+96-1)d
=>147=3(2a+5d)
147=6a+15d——(ii)
Therefore a+5d=37—-(i)
6a+15d=147—–(ii)
divide equation ii by 3
2a+5d=49–(ii)
multiply eq i by ii
=>a+10d=74
a+5d=49
5d/5=25/5
therefore d=5
substitute for d in eq i
a+5d=37
a+5(5)=37
a=37-25
a=12
The first term=12

(4b)
Sn=n/2[2a+(n-1)d]
S15=15/2[2(12)+(15-1)5]
=15/2(24+(14*5)
=7.5(24+70)
=705
========================================

(5a)
Let bag =B
shoe=S
U=120
n(BnS)=45,
n(S)=x+11
n(B)=x
n(SnB^1)=x+11-45
=x-34
n(BnS^1)=x-45

(5b)
DRAW THE VENN DIAGRAM
x-45+45+x-34=120
2x-34=120
2x=120+34
2x/2=154/2
x=77
=11+x
=11+77=88
Therefore 88customers bought shoes

(5c)
Pr(bag)=n(B)/U=77/120

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